A stone is dropped from the top of a tower and it is found to travel 7/16 of height of tower during the last second of its fall . The height of tower is (g=10 m/s^2)
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Answer:
80m
Explanation:
Using 4th equation of motion,
Distance in last second = a(t-0.5)
take total distace as ½gt² = 5t²
7/16h = 35/16t²
So, 35/16t² = 10t - 5
=> 35t² = 160t - 80
=> 35t² - 160t +80 =0
=> 7t² - 32t +16 = 0
This is a quadratic equation in t.
By solving, we get t = 4seconds.
So height of tower is 5t² = 5 x 16 = 80m
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