Question

A stone is dropped from the top of a
tower and it strikes with 3 km/hr
against the ground. Another stone is
thrown vertically downwards from the
same top of the tower with a velocity
4 km/hr. Its velocity when it strikes
the ground will be​

Answer 1

Answer:

Thevelocityoffirststoneonreachinggroundinthem/sis3×185=65m/sSov2=2gh⇒(65)2=2ghwherehistheheightofthetower,Nowforthesecondstonetheupwardinitialspeed=downwardinitialspeed=4×185=910m/sv2=u2+2gh⇒v2=(65)2+(910)2=1.929(m/s)2×(518)