Question

A stone is dropped from the top of a tower which touches the ground after 2 seconds. Calculate the speed of the stone hitting the ground surface. (g=10m/s ^ 2)​

Answer 1

Given:

Initial velocity(u) = 0

Time(t) = 2s

Acceleration due to gravity(g) = 10m/s²

Using equation of kinematics, we have

v = u + gt

v = 0 + 10 × 2

v = 10 × 2

v = 20m/s

Additional Information

Three equations of motion:

v = u + at

s = ut + 1/2 at²

v² = u² + 2as

Equations of kinematics:

v = u + gt

h = ut + 1/2 gt²

v² = u² + 2gh

Answer 2

Answer:

20 m

The tower is 20 meters tall.

Explanation:

Magnitude is a term used in physics to describe an object's maximal direction and size. Scalar and vectors elements both use magnitude as a common link. We are aware that scalar quantities are those that have just magnitude by design. Those quantities with both size and direction are considered vector quantities. Magnitude is essentially "length or amount" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in science typically refers to a size or quantity. Amplitude is a term that refers to size or importance. The magnitude of the movement is more than or equivalent to the distance. Velocity is the rate at which a displacement evolves over time.

Stone's initial movement speed $u = 0 m/s$

How long did it take the stone to fall to the ground $t = 2 sec$

Height of the tower

$H=ut+\frac{1}{2} at^{2}$

$H=0+\frac{1}{2} *10*2^{2}$

$H=20m/s$

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