Question

A stone is dropped in well which is 19.6 m deep. Echo sound is heard
after 2.06 sec (after dropping), then the velocity of sound is
1)332.6m/s
2)326.7m/s
3)300.4m/s
4)290.5m/s
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Answer 1

Answer:

Explanation:

Sound waves are transmitted downwards into the sea at the depth of 3100 m with the help of SONAR. technique. After how much time, au echo will be heard?

Answer 2

(2)The velocity of the sound is 326.7 m/s.

Explanation:

Given  height of the well, s = 19. 6 m and echo sound is heard after time,

T = 2.06 s.

Now calculate the time taken by the stone to reach bottom of the well ( sound to travel down) by using the second equation of motion.

$s=ut+\frac{1}{2}gt^2$.

Here, u is the initial velocity of the stone.

As stone is dropped from the height 19.6 m, so u = 0.

Substitute the given values, we get

$19.6m=0+\frac{1}{2}\times9.8m/s^2\times t^2$

t = 2 s.

Time taken by sound to travel up = 2.06 s - 2 s = 0.6 s.

Therefore, the velocity of the sound is

$v_{sound}=\frac{19.6m}{0.6s}$

$v_{sound}=326.67m/s$.

Thus, the velocity of the sound is 326.7 m/s.

#Learn More :

Topic : equation of motion.

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