Question

A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well.
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Answer 1

Answer:

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Explanation:

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Answer 2

Given, acceleration of stone is a=g=9.8m/s

2

Initial velocity is u=0m/s

Time for hitting water is t=3.41s

If d be the depth of the well.

Using d=ut+at

2/2,

∴ d=0(3.41)+0.5(9.8)(3.41)

2

=56.98∼57m