A stone is dropped into a well of depth 78.4 m .The impact of stone with water is heard after 4.28s . Find the speed of sound in air (g=9.8m/s^2)
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Answer:
height : 78.4m
v=0m/s
u=?
g= 9.8m/s²
T = 4.28 sec
v²-u²=2gh
(0)²-(u)²= 2×9.8×4.28
u²=83.888
u=√83.888
u=9.16 m/s (approx.)
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