Question

a stone is dropped into a well of depth h then the sound of splash is heard after the time of t what is the time to hear Splash of sound

Answer 1

hey mate here is your answer.....


sound of splash = the height of well.....


hope it helps you...

:-)

Answer 2

Explanation:

For the 1st part the stone is falling under gravity. Let t1 be the time from release to splashdown.

d =depth

So d=12gt21  (1)

After splashdown the sound travels back up. Using 330m/s for the speed of sound this gives:

d=330×t2  (2)

We also know that:

t1+t2=2s  (3)

Combining (1)and(2) we get:

330t2=12g.t21

From (3)⇒

t2=(2−t1)

So:

330(2−t1)=12.gt21

660−330t1=12.gt21

12gt21+330t1−660=0

Using the quadratic formula to solve for t1:

t1=−330±√(330)2−4×9.82×(−660)9.8

Ignoring the -ve root this gives:

t1=1.94s

So t2=2−1.94=0.06s

So d=330×t2=330×0.06=19.8m