Question

a stone is dropped into well 44.1m deep the sound of splash is heard 0.13 sec. after the stone hits the water what should be the velocity of sound in air ​

Answer 1

Answer:

Time taken by the stone to reach the water surface can be calculated using the equation of motion s = ut + ½ gt2 Here u = 0,

s = 44.1 m ,

g = 9.8 m/s2

So t = (2x44.1/9.8)½ = 3 s Therefore time taken by sound to travel this distance = 3.13 - 3 = 0.13 s Speed of sound in air = distance covered/Time = 44.1 m/ (0.13 s)

= 339.23 m/s