a stone is fall from top of tower if time of flight is 8s then how much time will it take to cover the second quarter of the distance starting from top
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H = 0.5gT^2
= 0.5 × 10 × 8^2
= 320 m
Height of the building is 320 m
Time taken to travel 1st half of the distance
s = 0.5gt^2
t = sqrt(2s / g)
t = sqrt(2 × 160 / 10)
t = sqrt(32) seconds
Time taken to travel 1st quarter (1/4th) of the Distance
t’ = sqrt(2s’ / g)
t’ = sqrt(2 × 80 / 10)
t’ = sqrt(16) seconds
Time taken to cover 2nd quarter distance = Time taken to cover 1st half distance - Time taken to cover 1st quarter of distance
= sqrt(32) - sqrt(16)
= 1.65 seconds
= 0.5 × 10 × 8^2
= 320 m
Height of the building is 320 m
Time taken to travel 1st half of the distance
s = 0.5gt^2
t = sqrt(2s / g)
t = sqrt(2 × 160 / 10)
t = sqrt(32) seconds
Time taken to travel 1st quarter (1/4th) of the Distance
t’ = sqrt(2s’ / g)
t’ = sqrt(2 × 80 / 10)
t’ = sqrt(16) seconds
Time taken to cover 2nd quarter distance = Time taken to cover 1st half distance - Time taken to cover 1st quarter of distance
= sqrt(32) - sqrt(16)
= 1.65 seconds
aiimsonite:
Thanks
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