Question

a stone is falling freely and describes a distance s in t second given by the equation s=1/2gt2. the acceleration of stone is

Answer 1

t, v is the initial velocity of the object, g is gravity (-9.8 m/s² at sea level), and c is the initial height of the object. So, given:

h(3.4)=0

we have:

0=-4.9(3.4)²+(3.4)v+12

3.4v=44.644

v=13.131 m/s as the original velocity of the stone...