A stone is fastened to one end of a string and is whirled in a vertical circle of radius R. Find the minimum speed the stone can have at the highest point of the circle. In its solution we do T+ mg= mv^2/r and T min=0 Here why we take mv^2/r? mv^2/r and mg both are towards down then why stone is in the air? What force is acting on it to keep it in air?? Thanks!
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As the stone is moving in circles, the force acting on it centrifugal force which is represented by mv²/r
The centrifugal force acts outwards, so when the body is at bottom the force will act downwards and top centrifugal force acts upwards.
For the minimum speed, the force is tends to be equal to the weight of the body. This is the reason he body keeps rotating in air.
The centrifugal force acts outwards, so when the body is at bottom the force will act downwards and top centrifugal force acts upwards.
For the minimum speed, the force is tends to be equal to the weight of the body. This is the reason he body keeps rotating in air.
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Hey! Stone is not in the air !!
Mv²/r is not centripetal force it is centrifugal force ...which is acting on the block upward ! And min. T is 0!
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