Question

a stone is gently released from top of the building. It strikes the ground in 5 sec. Find height of the building. Take value of acceleration as 10m/s/s.

Answer 1

Step-by-step explanation:

Distance (s) =20 m

Initial velocity =0 m/s

g=10 m/s

2

By using the formula:

v

2

=u

2

+2as

v

2

=0

2

+2×10×20

v

2

=400

v

2

=

400

v=20m/s

For calculating time:

V=u+at

20=0+10×t

t=

10

20

t=2 sec

The the stone will hit the ground with a velocity of 20 m/s in sec.