Question

a stone is projected at An angle of 30 degree with the ground with a velocity 39.2m/s. find horizontal range of stone.

Answer 1

angle of the projectile = ∅ = 30°

resultant initial velocity = u = 39.2m/s

acceleration due to gravity = g = 10m/s²

Horizontal range = R = ?
_______________________________

R = u²sin2∅/g

R = (39.2)²sin(2×30)/10

R = 1536.64×sin60°/10

R = 153.664 × √3/2

R = 76.83√3 m
OR
R = 133.08 m