Question

A stone is projected horizontally with speed v from a height h above ground. A horizontal wind is blowing in direction opposite to velocity of projection and gives the stone a constant horizontal acceleration f ( in direction opposite to initial velocity ). As a result the stone falls on ground at a point vertically below the point of projection. Then find the value of f2h/gv2 ( g is acceleration due to gravity ).​

Answer 1

Answer:

Explanation:

Dear student,

During the time of flight the particle must have zero horizontal displacement.

Time of flight=t_f=\sqrt{\dfrac{2h}{g}}

Hence since the horizontal displacement is zero,

0=ut_f-\dfrac{1}{2}ft_f^2

\implies \dfrac{2u}{f}=t_f=\sqrt{\dfrac{2h}{g}}

\implies \dfrac{4u^2}{f^2}=\dfrac{2h}{g}

\implies h=\dfrac{2u^2g}{f^2}