The perimeter of a rectangular metal plate is 36 dm and its area is 80 dm2.Find its dimentions.
Answers
Step-by-step explanation:
The perimeter of a rectangular shop in the mall is 36 meters. The area is 80 square meters. What are the dimensions of the shop?
We are told this is rectangular.
The perimeter of a rectangle is 2L + 2w. This means 2L + 2w = 36 which can be divded by 2 to reduce to L + w = 18.
The area of a rectangle is (L)(w). This makes the area equation: (L)(w)=80.
You could try guess and check with whole number answers:
L=1, w=17 area 17m², too small
L=2, w=16 area 32m², too small
L=3, w=15 area 45m², too small
L=4, w=14 area 56m², too small
L=5, w=13 area 65m², too small
L=6, w=12 area 72m², too small
L=7, w=11 area 77m², too small
L=8, w=10 area 80m², just right (or L=10 and w = 8)
Or you could write a system of equations and solve.
L+w = 18, subtract w from both sides; L = (18 - w)
(L)(w) = 80; substitute (18 - w) into the equation for L, (18 - w)(w)=80
18w - w² = 80; add w² to both sides
w² + 80 = 18w; subtract 18w from both sides
w² - 18w + 80= 0.
Now solve by your favorite method for solving quadratic equations.
Solve by factoring:
(w - 10)(w - 8) = 0
w - 10 = 0; add 10 to both sides, w = 10
or w - 8 = 0; add 8 to both sides, w = 8
The dimensions of the shop are 8m x 10m, or 10m x 8m.
Question:-
The perimeter of a rectangular metal plate is 36 dm and its area is 80 dm2.Find its dimentions.
Answer:-
- Length = 10 dm
- width = 8 dm
Solution:-
- x=width (shorter dimension)
- let y=length
set up 2 equations, one for perimeter and the other for area
2x+2y=perimeter=36
x*y=area=80
Substitute value of y in eq 2
- Value of x is 8 dm
- Value of y = 80/x = 80/8= 10 dm
Hence,
- width=8 cm
- length=10 cm