Question

A stone is projected with a velocity of 19.6 m / s and at 30 ° to the horizontal. Calculate (i)

range, (ii) total time of motion and (iii) maximum height​

Answer 1

Time of flight of projectile is given by formula,

T = (2 × u × sin(theta))/g

Where u is initial velocity, g is acceleration due to gravity, and theta is angle made by initial velocity with horizontal.

Given in the problem, theta = 30 degree, initial velocity is 19.6 m/s and g =9.8 m/s^2.

T = (2 × 19.6 × (1/2))/9.8

T = 19.6/9.8 = 2

T = 2 seconds.

Hope this will help.