A stone is projected with velocity 80 metre per second making an angle 30 with the horizontal the horizontal component of its velocity after 2 second
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Vertical component is 80sin30=40m/s
displacement of particle at t= 2 sec in verticle
= S =ut + 1/2at^2
=40*2 +1/2*(-10)2*2
=60 m
horizontal range = u^2sin¢^2/2g
60*20= u^2sin¢^2
usin¢=√1200=20√3
displacement of particle at t= 2 sec in verticle
= S =ut + 1/2at^2
=40*2 +1/2*(-10)2*2
=60 m
horizontal range = u^2sin¢^2/2g
60*20= u^2sin¢^2
usin¢=√1200=20√3
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