Question

a stone is release from the the top of a tower of height 20 m then its final velocity bye just before touching the ground will be(take g=10m/ s2)

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Answer 1

plz refer to the attachment above

Answer 2

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GIVEN

A stone is release from the the top of a tower of height 20 m

TO DETERMINE

The final velocity just before touching the ground

CALCULATION

By the given condition

Initial Velocity = u = 0 m/s

Height = h = 20 metre

$\sf{ g\: = 10 \: \: m /{s}^{2} \: }$

We are aware of the equation that

$\sf{ {v}^{2} \: = {u}^{2} + 2gh \: }$

$\implies \: \sf{ {v}^{2} \: = {(0)}^{2} + 2 \times 10 \times 20 \: }$

$\implies \: \sf{ {v}^{2} \: = 400 }$

$\implies \: \sf{ {v}\: = \: 20}$

Hence the final velocity just before touching the ground is 20 m/s

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LEARN MORE FROM BRAINLY

Divergence of r / r^3 is

(a) zero at the origin

(b) zero everywhere

(c) zero everywhere except the origin

(d) nonzero

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