A stone is released fro:m the top of a tower of height 16.6 1m calculate it's flnal velocity before touching the ground.
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Answer:
it's physics but it's about physics
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Answer:
17.9 m/s
Explanation:
Stone is dropped from a height of 16.61 m
⇒ u = 0, v = v , a = g = 10 m/s² [freely falling body case]
We know that
s = ut + 1/2 *a*t²
⇒h = ut + 1/2 *a*t²
⇒16.61 = 0 + 1/2 * 10 t²
⇒16.61 = 5t²
⇒t² = 16.61/5 = 3.32
⇒t = 1.79 sec
we know that
v = u + at
⇒v = 0 + 10*1.79
∴v = 17.9 m/s
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