Question

A stone is released from the top of a lower of height 19.6 m calculate its final velocity just before touching the ground​

Answer 1

Answer:

final velocity =19.6m/s

Explanation:

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v^2 =u^2+2gs

v^2=0+2×9.8×19.6

v^2=384.16

⇒v=19.6m/s....

here is your answer me.

hope it helps

Answer 2

Answer:

Hope my answer helps you..