Question

a stone is released from the top of a tower of height 19.6 m. The final Velocity just before touching the ground is the answer is 19.6 ms-1 right or wrong​

Answer 1

Answer:

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v

2

=u

2

+2gs

v

2

=0+2×9.8×19.6

v

2

=384.16

⇒v=19.6m/s

hope its help u

Answer 2

Answer:

Answer. v = ? Hence, the velocity of the stone just before touching the ground is 19.6 ms^−1