Question

A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.

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Answer 1

height = 19.6 m

initial velocity = 0 ms^-1

final velocity = ?

g = 10 ms^2

we know v^2 = u^2 + 2gh

v^2 = 0 + 2.10.19.6

v^2 = 392

v = √392 = √(2×2×2×7×7)= 14√2 ms^-1

thus final velocity is 14√2 ms^-1

Answer 2

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