A stone is released from the top of a tower of height 19.6m . calculate it's final velocity
Answers
Answered by
10
U= 0
a = 9.8 m/sec square
s = 19.6 m
USING THIRD EQUATION OF MOTION
v square = u square + 2as
v square = 0 + 2 × 9.8 × 19.6
v square = 384.16
v = √384.16
v = 19.6 m/sec
ANSWER = 19.6 m/sec
HOPE IT HELPS :):):):):)
MARK AS BRAINLIEST
a = 9.8 m/sec square
s = 19.6 m
USING THIRD EQUATION OF MOTION
v square = u square + 2as
v square = 0 + 2 × 9.8 × 19.6
v square = 384.16
v = √384.16
v = 19.6 m/sec
ANSWER = 19.6 m/sec
HOPE IT HELPS :):):):):)
MARK AS BRAINLIEST
Similar questions