Question

A stone is released from the top of a tower of height 19.6m.calculate its velocity just before touching the ground .A man weight 600 N on the surface of earth what would be his mass and weight on the surface of the moon?

Answer 1

u= 0

a = 9.8 m/sec square

s = 19.6 m

USING THIRD EQUATION OF MOTION

v square = u square + 2as

v square = 0 + 2 × 9.8 × 19.6

v square = 384.16

v = √384.16

v = 19.6 m/sec

ANSWER = 19.6 m/sec

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