Question

answer for this is 3/4 . how can someone pls explain

Answer 1

Answer:

The answer can be 4/3 just check it once

Step-by-step explanation:

Limit(x->0) (2x-sin2x)/x^3

If we directly apply limit we get 0/0 which is indeterminate form

so differentiate both numertaor and denominator

apply first derivation

limit(x->0)(2-2cos2x)/3x^2

now limit(x->0) 2(1-cos2x)/3x^2

limitx->0 2(2sin^2x)/3x^2

limitx->0 4sin^2x/3x^2

now limitx->0 sinx/x=1

So by using that we get

(4/3) limitx->0 sin^2x/x^2

4/3*1

=4/3