Question

a stone is released from the top of the tower of height 19.6 calculate its final velocity touching the ground ​

Answer 1

Answer:

initial velocity=0

final velocity or v =?

height= 19.6m

By third equation of motion

V^2=U^2+2gs

V^2=0+2 X 9.8 X 19.6

V^2 = 384.16

➡V= 19.6 m/s

hope it helps ;)