Question

A stone is released from the top of the town of height 19.6m calculate its final velocity before touching the ground

Answer 1

According to Motion formulae,


Initial Velocity = 0

Height = 19.6m

Acceleration = 9.8m/s² due to gravity

(Final Velocity)² = (Initial Velocity)² + 2*Acceleration*Height

(Final Velocity)² = 0 + 2*9.8*19.6

(Final Velocity)² = (19.6)²

Final Velocity = 19.6 m/s

So, your answer is 19.6 m/s.


Thank you.

Answer 2

u=0m/s
acceleration=9.8m/second square (10m/s square as approx)
height=19.6metre
v=?
: according to second equation of motion,
$v {?}^{2} - u {?}^{2} = 2as$
$v {?}^{2} = 2 \times 10 \times 19.6$
$v {?}^{2} = 392$
$v = \sqrt{392}$
now you find this