A stone is released from the top of tower of height 19.6 m calculate final vel
Answers
Answered by
4
Final velocity = (2gh)^1/2
= (2*9.8*19.6)*1/2
=(19.6*19.6)^1/2
Final vel = 19.6 m/s
Thank You
Hope this answers your question
If you don’t mind please mark it as Brainliest answer
= (2*9.8*19.6)*1/2
=(19.6*19.6)^1/2
Final vel = 19.6 m/s
Thank You
Hope this answers your question
If you don’t mind please mark it as Brainliest answer
Answered by
0
Initial velocity,u = 0 m/s
Acceleration due to gravity, g = 9.8 m/s^2
Height of tower, H = 19.6 m
Final velocity of the stone, v = ?
From the equation v2 = u2 + 2as —>
v2 = u2 + 2gH
v2 = 0^2 + 2 * 9.8 m/s2 * 9.8 m
v = €384.16 m2s-2 = 19.6 ms-1
Attachments:
Similar questions