a stone is released from the top of tower of height 19.6 m. calculate the final velocity just before touching the ground
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v = 19.6m/s
Explanation:
Given that
Initial velocity u = 0
Tower height = total distance = 19.6m
g = 9.8 m/s2
Find out , Final velocity just before touching the ground.
Solution:Let us solve using third equation of motion
v2 = u2 + 2gs
v2 = 0 + 2 × 9.8 × 19.6
v2 = 384.16
v = √(384.16)
v = 19.6m/s
Final velocity just before touching the ground = v = 19.6m/s
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