Question

A stone is released from the top of tower of the height 1960 m.
a) Calculate the time takerby the stone to hit the ground.
b) Find the velocity with which it hits the ground.
​

Answer 1

Answer:

this pic is a part

b)Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v

2

=u

2

+2gs

v

2

=0+2×9.8×19.6

v

2

=384.16

⇒v=19.6m/s

plz tag it as brainlist