Question

A stone is released from top of a tower of height 44.1 m. with what velocity and in how much time does it reach the earth? (g=9.8m/s²). ​

Answer 1

Explanation:

Initial Velocity u=0

Fianl velocity v=?

Height, s=19.6m

By third equation of motion

v²=u²+2gs

v²=0²+2(9.8)(19.6)

v²=384.16

v²=√384.16

v=√38416/100

v=196/10

v=19.6

Therefore,v=19.6

Answer 2

Answer:

Ask on Google plz.......

Explanation:

Google is our best teacher