Question

A stone is throne horizontally form a 200m cliff and lands at a distance of 0.312km. What was its initial velocity?

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Answer 1

Answer:

no idea mate.............sorry..............

Answer 2

Given:

The range of the stone, R = 0.312 km = 312 m

The height of the cliff, h = 200 m

To Find:

The horizontal velocity of the stone, i.e., u.

Calculation:

- For a projectile motion, the range is given as:

R = u √(2h / g)

⇒ u = R √(g / 2h)

- Putting all the known values and g = 10 m/s², we get:

⇒ u = 312 √(10 / 2 × 200)

⇒ u = 49.33 m/s

- SO, the initial velocity of the stone is 49.33 m/s.