Question

a stone is thrown at an angle of 30 degree to the horizontal with a velocity of 40m/s on a level ground calculate a) maximum height reached by the stone b) maximum horizontal distance covered​

Answer 1

Answer:

40 if g is considered to be 10m/s²

Explanation:

H=u²sin 30⁰/2g

H=(40 X 40 X 1/2)/2 X 10=40m