A stone is thrown at angle of oº from a height of
100 m with 8ms-1 After 0.6 sec, its velocity will
be:
Option A:
Zero
Option B
13.6 ms
Option
8 ms -7
Option
10 ms.
Ans D solution?
Answers
Answered by
0
Explanation:
x component of velocity remains constant through out the journey.
Attachments:
Answered by
2
Answer:
Explanation:
here s=100m
u=8m/s
t=0.6sec
a=g=9.8m/s²
V=u+at
V=8+(9.8)(0.6)
V=8+5.88
V=13.88
V=13.9
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