A stone is thrown from at an angle of 30° down with the horizontal with the velocity of 25m/sec if stone strikes the water after 2.5 sec then calculate the height of bridge from water surface
Answers
Answered by
30
hey mate here is ur ans
given: angle = 30°
velocity = u = 25m/s
time : 2.5 sec
let g = 10
firstly we know that formula i.e.
height = [u*sin( theeta)] ^2 / 2g
[25sin(30°)]^2/2*10
( 625*1/2)^2 /20
( 312.5)^ 2/20
97656.2/20
4882.8 m
4km 900m apprx
hope it help u
given: angle = 30°
velocity = u = 25m/s
time : 2.5 sec
let g = 10
firstly we know that formula i.e.
height = [u*sin( theeta)] ^2 / 2g
[25sin(30°)]^2/2*10
( 625*1/2)^2 /20
( 312.5)^ 2/20
97656.2/20
4882.8 m
4km 900m apprx
hope it help u
Answered by
19
Answer:
61.9 m
Explanation:
how can I found my correct answer
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