Question

a stone is thrown horizontal with speed 30m/s from a tower of height 50m. the height of stone from ground at which it makes 45degree with horizontal is

Answer 1

height of stone , h = -50m [ taking reference level is at 50m above from ground]
horizontal initial speed of stone , $u_x$=30m/s.
vertical initial speed of stone , $u_y$ = 0m/s

at ground ,
horizontal speed , $v_x=u_x=30m/s$
vertical speed ,
$v_y=\sqrt{u_y^2+2gh}$
$v_y=10\sqrt{6}$

now, $v=\sqrt{600+900}=10\sqrt{15}$

now, stone is projected with speed 10√15 at an angle of projection is 45° with horizontal.
so, maximum height = u²sin²θ/2g
= (1500)² × sin²45°/2 × 10
= (1500) × 1/2/20
= 1500/40
= 37.5 m

Answer 2

Answer:

pls mark as brainlist if it is correct

Explanation: