Question

A stone is thrown horizontally from an elevated point. After 0.5 seconds, the magnitude of its

velocity is 1.5 times the magnitude of its initial velocity. Find the initial speed of stone​

Answer 1

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initial velocity=u

final velocity=v=1.5u

t=0.5s

v=u+at

=>1.5u=u+ax0.5

=>a=u

S=ut+at2/2

=>S=0.625u

We can get one unknown if 2 are known in each equation of motion. But in every equation we have two unknown quantities.

Hence it is not possible to find exact values of initial velocity until acceleration or distance travelled in 0.5s is given.

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