Question

A stone is thrown in a vertically<br />upward direction with a velocity<br />of 5 ms-1. If the acceleration of the<br />stone during its motion is 10m s-2<br />in the download direction, what<br />will be the height attained by the<br />stone and how much time will it<br />taice to reach there?<br /><br />please don't give me direct answers ​

Answer 1

Answer: 0.5 os your answer

Explanation:

To find the height attained,

v2 = u2 + 2as

s = Height attained = (v2 - u2)/2a = (0 - 25)/(2 x -10) = 1.25 .

a is negative since it's direction is opposite to the direction of motion.

t = (v - u)/a = -5/-10 = 0.5 s.

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