Question

A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10m/s^2 in the downward direction. What will be the height attained by the stone and how much time will it take to reach there?

Answer 1

Answer:

As given that

u, = 5

a, = -10

v, = 0

By using

v= u +at

0 = 5+(-10)T

-5 = -10 T

t = 1/2=0.5

s=ut+1/2at ^2

s = 5(1/2) + 1/2(-10) ×1/4

s = (5/2-5/4) m

s = (10-5 / 4) m

s = 5/4 m

--------------answer = s, = 1.25m

hope it will help you