Question

A stone is thrown in a vertically upward direction with a velocity of 5 m s −1 . If the acceleration of the stone during its motion is 10 m s −2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Answer 1

Answer:Hsjsj

Explanation:

Answer 2

Hey Dear,

◆ Answer -

s = 1.25 m

t = 0.5 s

● Explaination -

# Given -

u = 5 m/s

a = -10/s^2

# Solution -

Let t be time taken for the stone to reach max height where v = 0 m/s,

v = u + at

0 = 5 - 10t

t = 5/10

t = 0.5 s

Now, maximum height attained by the stone is calculated as -

s = ut + 1/2 at^2

s = 5×0.5 + 1/2 (-10) × 0.5^2

s = 2.5 - 1.25

s = 1.25 m

Hope this helps.