a stone is thrown in a vertically upward direction with a velocity of 5 m per sec.If the acc. of the stone diring its motion is 10 m per second square in the downward drection,what will be the height attained by the stone amd how much time will it take to reach there
Answers
Answered by
21
Explanation:
v=u+at
-5 = (-10) t...(-ve sign indicates acceleration is in opposite directions)
t = 0.5 sec
S = ut +1/2 at^2
S = 2.5 + 1/2 10×2.5
= 2.5+12.5
S = 15 m
Total time = 0.5+0.5=1s
Total time = 0.5+0.5=1sand max height = 30 m
Hope it helps uh!
Similar questions