Question

A stone is thrown in a vertically
upward direction with a velocity
of 5 ms. If the acceleration of the
stone during its motion is 10 ms?
in the downward direction, what
will be the height attained by the
stone and how much time will
tale to reach there?​

Answer 1

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Answer 2

Answer:

Maximum height = 1.25 metres

Time taken to reach the maximum height = 0.5 seconds

Explanation:

Given:

• Initial velocity = u = 5 m/s

• Acceleration in upward direction = -10 m/s²

To find:

• Height attained by the stone
• Time taken for the stone to reach the highest point

The final velocity, that is the velocity of the stone at the highest point will be equal to 0 (v = 0 m/s)

Now using third equation of motion:

V²-u²=2as

0²-5²= 2×-10×s

-25=-20s

s = $\frac{-25}{-20}$

s = $\frac{25}{20}$

s = 1.25 metres

The maximum height reached by the stone is equal to 1.25 metres

Now using second equation of motion:

S=ut+$\frac{1}{2}$at²

1.25=5×t+$\frac{1}{2} \times -10 \times t^{2}$

1.25=5t-5t²

-5t²+5t-1.25

Solving the above, we get t = 0.5 seconds

The time taken to reach the maximum height is equal to 0.5 seconds