Question

A stone is thrown in a vertically upward direction with a velocity of 10 m/s. If the acceleration of the stone during its motion is 10 m /s2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
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Answer 1

Answer:

initial velocity (u) = 10 m/s

final velocity (v) = 0 m/s

acceleration (a) = -10 m/s²

to find : displacement (s) and time (t)

sol: According to the 3rd law of motion,

2as = v²-u²

2×(-10)×s = 0²-10²

-20s = 0-100

-20s = -100

s = -100/-20 = 5

so, displacement by the stone = 5 m

According to the 1st law of motion,

v = u+at

0 = 10+-10×t

0 = 10-10t

-10t = -10

t = -10/-10 = 1

so, time taken by the stone = 1 second