Question

A stone is thrown in a vertically
upward direction with a velocity
of 5 ms. If the acceleration of the
stone during its motion is 10 m s2
in the downward direction, what
will be the height attained by the
stone and how much time will it
take to reach there?


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Answer 1

Given, initial velocity, u=5ms −1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms −2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v 2 −u 2 =2as, we have

s=v 2 −u 2 /2a

=(0) 2 −(5) 2 /2×(−10) = 1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s

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