Question

A stone is thrown in a vertically upward direction with a velocity of 5m/s.If the acceleration of the stone during its motion is 10 m/s in the downward direction, What will be the height attained by the stone and how much time will it take to reach there?​

Answer 1

$\huge\bigstar\underline\mathfrak{Answer:-}$

Given:-

Initial velocity (u) = 5m/s

Final velocity (v) = 0m/s

Acceleration (a) = -10m/s

height i.e., distance (s) = ?

Time (t) taken to reach the height = ?

We know that,

${v}^{2} = {u}^{2} + 2as$

$0 = {(5)}^{2} + 2 \times - 10 \times s$

$0 = 25 - 20s$

$s = \frac{25}{20} m$

$s = 1.25m$

Now, we know that,

$v = u + at$

$0 = 5 + ( - 10) \times t$

$0 = 5 - 10t$

$t = \frac{5}{10} s$

$t = 0.5s$

Thus, stone will attain a height of 1.25m and time taken to attain the height is 0.5s.

Answer 2

Answer:

Given:-

Initial velocity (u) = 5m/s

Final velocity (v) = 0m/s

Acceleration (a) = -10m/s

height i.e., distance (s) = ?

Time (t) taken to reach the height = ?

We know that,

v² = u² + 2as

0 = 5² + 2 × -10 × s

0 = 25 - 20s

s = 25/20 m

s = 1.25 m

Now, we know that,

v = u + at

0 = 5 + (-10) × t

0 = 5 - 10t

t = 5 / 10 s

t = 0.5 s

∴ Stone will attain a height of 1.25m and time taken to attain the height is 0.5s.

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