Question

- A stone is thrown in a vertically upward direction with a velocity of 5
m s ‐². If the acceleration of the stone during its motion is 10 ms‐² in
the downward direction, what will be the height attained by the
stone and how much time will it take to reach there?​

Answer 1

Answer :

A stone is thrown vertically upward with a velocity of 5m/s.

Acceleration due to gravity = 10m/s²

We have to find max. height attained by the stone and time taken to reach there$.$

_________________________________

◈ For a body thrown vertically upward, g is taken negative.

❍ Max. height :

➝ v² - u² = 2gH

➝ 0² - 5² = 2(-10)H

➝ -25 = -20H

➝ H = -25/-20

➝ H = 1.25 m

❍ Time taken :

➝ v = u + gt

➝ 0 = 5 + (-10)t

➝ t = -5/-10

➝ t = 0.5 s