A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10m/s2 in the downward direction , what will be the height attained by the state and how much time will it take to reach there
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Answer:
Hi there!!!
Explanation:
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refer to the picture....
Attachments:
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Explanation:
v=u+at
0=5+(-10)t
5=10t
5÷10=t
0.5=t
again using equation of motion
2as=vsquare-usquare
2×(-10)×s=0square-5square
-20s=-25
s= -25÷-20=5/4
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