Physics, asked by niyatikarmur, 8 months ago

A stone is thrown in a vertically upward direction with a velocity of 10 m/s. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Answers

Answered by mbakshi37
0

Answer:

a. 5 m

b. 1 sec

Explanation:

Concept : at Max hieght all initial KE has converted to Potential Energy.

u^2 = 2 g Hmax

Hmax= 10x10/2/10= 5 meters

Concept : Time to reach Max hieght When final velocity is Zero

0= u-gT

T = u/g= 10/10= 1 Sec.

Answered by Anonymous
3

Answer:

Concept : at Max hieght all initial KE has converted to Potential Energy.

u^2 = 2 g Hmax

Hmax= 10x10/2/10= 5 meters

Concept : Time to reach Max hieght When final velocity is Zero

0= u-gT

T = u/g= 10/10= 1 Sec.

Thanks..

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