A stone is thrown in a vertically upward direction with a velocity of 10 m/s. If the acceleration of the stone during its motion is 10 m /s2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
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Answer:
Given -:
Final velocity – 0m/s
Initial velocity – 10m/s
Acceleration – 10m/s²
Distance/ height – ?
Formula used -:
V²= U²+ 2as
S=U²– V²/ 2a
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