Question

a stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10m/s2 in downward direction what will be the height attained by the stone and how much time will it take to reach there?​

Answer 1

Initial velocity of stone (u) = 5m/s

final velocity of stone(v) =0 m/s

since the acceletration is in direction opposite to that of motion thus it causes retardation of the stones motion.

Thus using 3rd equation of motion

i.e.

$2as = {v}^{2} - {u}^{2}$

2(-10)s=0 - 25

-20s = -25

s = 25/20

s = 5/4

s = 1.25m